the counting to 100 thread

[iwishforducks]

Bottom post of the previous page:

this is a staple thread of any forum i cant believe we dont have one yet

the rules are simple, count from 1 to 100. counting counts if you count the count at the end of your post. if there's anything but the next number at the end of a post then we ALL have to start over at 1. you cannot double post.

[TheLoLSwat]

I hate you Arm I am giving up on my experiment

rules are from 1 to 100 anyway, you can mald all you want about it but when it goes from 1 to 100 its finished, FUCK using 0!

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Yeah... but I would break a chain that didn't have a 0 before the chain started... so that would be a de facto new rule. If people tried to abide and avoid me breaking it.

That was the whole experiment.

what are you experimenting its just you checking the thread every few hours to see if the thread started at 0 and punishing everyone for it if your conditions werent met

[Bawhoppennn]

The social experiment is seeing how people would respond and if they would even understand that it was a condition
Don't overthink it, this is a thread for silliness and that is what the tenor was when I made the post

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[TheLoLSwat]

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[Sightld2]

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[oranges]

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[Turbonerd]

We can get past 5.

[iwishforducks]

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[Turbonerd]

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[oranges]

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[Bawhoppennn]

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[CMDR_Gungnir]

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[conrad]

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[oranges]

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[san7890]

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[RaveRadbury]

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[san7890]

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[Sightld2]

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[san7890]

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[oranges]

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[RaveRadbury]

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[san7890]

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[Armhulen]

Let f(x) = x^3 + 2x^2 - 5x + 1. Find the value of the definite integral of f(x) from x = 0 to x = 3.

► Show Spoiler

∫[0,3]f(x)dx = F(3) - F(0) = [(1/4)(3)^4 + (2/3)(3)^3 - (5/2)(3)^2 + (3)] - [(1/4)(0)^4 + (2/3)(0)^3 - (5/2)(0)^2 + (0)] = [20.25 + 18 - 22.5 + 3] - [0] = 21

[Sightld2]

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[Armhulen]

The number of pairs of chromosomes in a human cell

[vect0r]

The number of pairs of chromosomes in a human cell

A: 24 B: 1

[Bawhoppennn]

Arm broke the chain by being incorrect about the chromosomes (yes it is wrong to say humans necessarily have 23 pairs of chromosomes, since there can be extra chromosomes; I am a counting thread stickler and any ambiguity is not allowed)
And then irregardless Vector broke it a second time by ending their confusing post with 1 instead of 24

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[san7890]

they ended their post in 1 you could've started with 2 bawhoppen

speaking of 2

[Bawhoppennn]

I guess I could have you're right Sans, maybe that was the point
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[scamoppi]

please i just wanna go home and see my family
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[CPTANT]

please i just wanna go home and see my family
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One must imagine Sisyphos happy.


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[Thunder11]

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[Not-Dorsidarf]

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[CMDR_Gungnir]

We're not allowed to be free.

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[Turbonerd]

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[conrad]

Arm broke the chain by being incorrect about the chromosomes (yes it is wrong to say humans necessarily have 23 pairs of chromosomes, since there can be extra chromosomes; I am a counting thread stickler and any ambiguity is not allowed)
And then irregardless Vector broke it a second time by ending their confusing post with 1 instead of 24

1.

Irregardless is not a word.

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[Itseasytosee2me]

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[Turbonerd]

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[conrad]

We getting to 1000
But not to 100
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[Armhulen]

yes it is wrong to say humans necessarily have 23 pairs of chromosomes, since there can be extra chromosomes

Well I'm sorry mr chromosome hogger, but while a human cell can have more than 23 chromosomes, it's an ABNORMALITY.


A car starts from rest and accelerates at a rate of 2 m/s^2 for 7 seconds. How far does the car travel during this time?
Something is sussy about this question I'm throwing it out
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[NoxVS]

I’m just glad we are out of the chain with calculus
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[Armhulen]

I’m just glad we are out of the chain with calculus
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Are you? Don't forget your No. 2 pencil for this standardized test.

Evaluate the integral ∫(4x^2)/(x^4+10x^2+9) dx from x=1 to x=3.

► Show Spoiler

I used trigonometric substitution to solve this.

Let x = 3tan(θ), then dx = 3sec^2(θ)dθ. Substituting this into the integral gives us:
= ∫36tan^2(θ)sec^2(θ)/(9tan^4(θ)+30tan^2(θ)+9)dθ
= ∫36/(tan^2(θ)+3)dθ
= ∫36/(sec^2(θ)-1+3)dθ
= ∫36/((sec^2(θ)+2))dθ
= 18ln(sec(θ)+sqrt(sec^(theta) + 8)) + C

Now we need to find the limits of integration in terms of θ.
Since x = 3tan(theta), we have theta = arctan(x/3).
So when x=1, theta = arctan((1/3)) and when x=3, theta = arctan((3/3)).

Therefore, our definite integral becomes:
18ln(sec(arctan((1/3)))+sqrt(sec^(arctan((1/3))) + 8)) - 18ln(sec(arctan((1)))+sqrt(sec^(arctan((1))) + 8)) ≈ 16

[conrad]

I’m just glad we are out of the chain with calculus
15

Are you? Don't forget your No. 2 pencil for this standardized test.

Evaluate the integral ∫(4x^2)/(x^4+10x^2+9) dx from x=1 to x=3.

► Show Spoiler

I used trigonometric substitution to solve this.

Let x = 3tan(θ), then dx = 3sec^2(θ)dθ. Substituting this into the integral gives us:
= ∫36tan^2(θ)sec^2(θ)/(9tan^4(θ)+30tan^2(θ)+9)dθ
= ∫36/(tan^2(θ)+3)dθ
= ∫36/(sec^2(θ)-1+3)dθ
= ∫36/((sec^2(θ)+2))dθ
= 18ln(sec(θ)+sqrt(sec^(theta) + 8)) + C

Now we need to find the limits of integration in terms of θ.
Since x = 3tan(theta), we have theta = arctan(x/3).
So when x=1, theta = arctan((1/3)) and when x=3, theta = arctan((3/3)).

Therefore, our definite integral becomes:
18ln(sec(arctan((1/3)))+sqrt(sec^(arctan((1/3))) + 8)) - 18ln(sec(arctan((1)))+sqrt(sec^(arctan((1))) + 8)) ≈ 16

Sorry I can't read.

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[Not-Dorsidarf]

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[Itseasytosee2me]

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[san7890]

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[HeyHey]

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[vect0r]

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[Armhulen]

The number of flavors in Dr. Pepper.

► Show Spoiler

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[LeekiLoku]

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[CPTANT]

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[TheLoLSwat]

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